Sabtu, 24 Oktober 2009

Tugas 2 Fisika Dasar














Menghasilkan 4 Geometri

2. a = 3i + 3j - 3k
b = 2i + j + 3k
jawab :
koordinat perpisahan
ab = selisih (b - a)
b = 2i + j + 3k
a = 3i + 3j - 3k -
= -i - 2j + 6k





























3. a = 4i - 3j + k
b = -i + j + 4k

a. a + b = ( 4i - 3j + k) + (-i + j + 4k)
= 3i - 2j + 5k
b. a - b = ( 4i - 3j + k) - ( -i + j + 4k )
= 5i - 4j -3k
c. vektor c agar a - b + c = 0
(a - b) = - c
5i - 4j - 3k = - c
c = -5i + 4j + 3k

4. a = 3i + 3j -3k
b = 2i +j + 3k
jawab :































5. a = 3i + 3j - 2k
b = -i - 4j + 2k
c = 2i + 2j + k
tentukan : a . ( b x c )
jawab :
cari b x c
b x c = i (bycz - cybz) - j (bxcz - bzcx) - k (bxcy - bycx)
= i (-4.1 - 2.2) - j (-1.1 - 2.2) -k (-1.2 - (-4)2)
= i (-4 - 4) - j (-1 - 4) - k (-2 + 8)
= -8i - 5j - 6k
a . ( b x c ) = 3i (-8i) + 3j (-5j) + (-2k)(-6k)
= -24 i - 15j + 12k

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